statement corollary
Distinct eigenvalues imply diagonalisable
Statement
Let be a field and let be an matrix over . If has pairwise distinct eigenvalues in , then is diagonalisable over .
Remarks
Eigenvectors for the distinct eigenvalues are linearly independent, so they form a basis of . The converse fails: is diagonal, but it has only one eigenvalue. For example, has eigenvalues and , so it is diagonalisable.
Explanations
L1 human
If an matrix has different eigenvalues, then it has independent eigenvectors. So it is diagonalisable. This sufficient condition is easy to check with the characteristic polynomial.
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To read this node, read these 22 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Identity matrix object
- Matrix definition
- Vector space definition
- Matrix multiplication definition
- Square matrix definition
- Linear combination definition
- Linear map definition
- Linear subspace definition
- Invertible matrix definition
- Diagonal matrix definition
- Linear independence definition
- Endomorphism definition
- Linear span definition
- Similar matrices definition
- Eigenvalue definition
- Spanning set definition
- Diagonalisable matrix definition
- Eigenvector definition
- Basis definition
- A matrix is diagonalisable iff it has a basis of eigenvectors statement
- Eigenvectors with distinct eigenvalues are linearly independent statement
- Distinct eigenvalues imply diagonalisable statement
Sources
- Web https://en.wikipedia.org/wiki/Diagonalizable_matrix, Characterization
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