statement theorem
The Galois group has order at most the degree
Statement
Let be a finite extension. Then the group of automorphisms of is finite, and
Remarks
For a simple extension , an automorphism is determined by , which is a root in of the minimal polynomial of . There are at most such roots. Equality holds if and only if is a Galois extension. For , the inequality is strict: .
Explanations
L1 human
A finite extension has only finitely many symmetries over the base field, and at most as many as its degree. When there are exactly as many as the degree, the extension is Galois.
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What this needs
To read this node, read these 14 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Ring homomorphism definition
- Subring definition
- Unit of a ring definition
- Ring isomorphism definition
- Field definition
- Subfield definition
- Field extension definition
- Degree of a field extension definition
- Galois group definition
- Finite extension definition
- The Galois group has order at most the degree statement
What depends on this
2 nodes use this node, directly or through other nodes.
Sources
- Web https://en.wikipedia.org/wiki/Galois_group, Cardinality of the Galois group and the degree of the field extension
- Web https://en.wikipedia.org/wiki/Galois_extension, Characterization of Galois extensions