statement theorem
Eigenvalues are the roots of the characteristic polynomial
Statement
Let be a field, let be a finite-dimensional vector space over , and let be a linear map. Let be the characteristic polynomial of , and let . Then is an eigenvalue of if and only if .
Remarks
The proof: is an eigenvalue if and only if is not injective, if and only if . So has at most eigenvalues. For , , so the eigenvalues are and .
Explanations
L1 human
To find the eigenvalues of a matrix, compute its characteristic polynomial and find its roots. Each root is an eigenvalue, and each eigenvalue is a root. Then, for each eigenvalue , solve to find the eigenvectors.
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What this needs
To read this node, read these 21 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Identity matrix object
- Matrix definition
- Vector space definition
- Square matrix definition
- Linear combination definition
- Linear map definition
- Linear subspace definition
- Linear independence definition
- Endomorphism definition
- Linear span definition
- Multilinear map definition
- Eigenvalue definition
- Spanning set definition
- Alternating multilinear map definition
- Basis definition
- Determinant definition
- Coordinate vector definition
- Characteristic polynomial definition
- Matrix of a linear map definition
- Characteristic polynomial of a linear map definition
- Eigenvalues are the roots of the characteristic polynomial statement
Sources
- Web https://en.wikipedia.org/wiki/Characteristic_polynomial, Formal definition
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