statement theorem
Rank–nullity theorem
Statement
Let be a field, let be a finite-dimensional vector space over , and let be a vector space over . Let be a linear map. Then that is, , with the rank and the nullity of .
Remarks
For an matrix , this says . A proof extends a basis of to a basis of ; the images of the new vectors form a basis of . The theorem also follows from the first isomorphism theorem .
Explanations
L1 human
Each dimension of the domain either survives in the image or is crushed into the kernel. So the dimensions of image and kernel add up to the dimension of the domain. A map from to has a kernel of dimension at least .
What this node needs for W2
- edge about out: the concepts that the statement is about (0 of 1)
- edge proves in: at least one proof node (0 of 1)
- edge instance_of or illustrates in: one example that shows the statement at work (0 of 1)
- explanation L2 (0 of 1)
The writing levels say how complete the text of a node is. They do not measure its truth.
What this needs
To read this node, read these 15 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Vector space definition
- Linear combination definition
- Linear map definition
- Linear subspace definition
- Linear independence definition
- Image of a linear map definition
- Kernel of a linear map definition
- Linear span definition
- Spanning set definition
- Basis definition
- Finite-dimensional vector space definition
- Dimension definition
- Rank of a linear map definition
- Nullity definition
- Rank–nullity theorem statement
What depends on this
1 node uses this node, directly or through other nodes.
Sources
- Web https://en.wikipedia.org/wiki/Rank–nullity_theorem, Stating the theorem