Adjoining a root of a polynomial
Definition
Let be a field and let be irreducible. The field obtained by adjoining a root of to is the quotient ring . The map , , identifies with a subfield, and the class is a root of .
Remarks
The quotient is a field, because is irreducible. Its degree over is , with the basis . For example, adjoining a root of to gives a field isomorphic to .
Explanations
L1 human
You can create a root of a polynomial that has none. Compute with polynomials in , and replace by zero each time it appears. This is how arises from and .
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What this needs
To read this node, read these 31 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Ideal definition
- Polynomial ring definition
- Unit of a ring definition
- Zero divisor definition
- Ideal generated by a subset definition
- Maximal ideal definition
- Two-sided ideal definition
- Field definition
- Degree of a polynomial definition
- Integral domain definition
- Principal ideal definition
- Quotient ring definition
- The only ideals of a field are zero and the whole field statement
- Irreducible element definition
- Leading coefficient definition
- Euclidean domain definition
- Correspondence theorem for rings statement
- Irreducible polynomial definition
- Principal ideal domain definition
- Monic polynomial definition
- Degree of a product statement
- R/M is a field iff M is maximal statement
- In a PID a nonzero element is irreducible iff it generates a maximal ideal statement
- Division algorithm for polynomials statement
- R[x] is an integral domain iff R is statement
- K[x] is a Euclidean domain statement
- K[x]/(f) is a field iff f is irreducible statement
- Adjoining a root of a polynomial definition
What depends on this
4 nodes use this node, directly or through other nodes.
- Existence of splitting fields 01441KDGBY
- Galois field 04SGPNT8R9
- Existence of finite fields of every prime power order 0T8M3YC5RG
- Every polynomial has a root in some extension field 0VG02M1FEZ
Sources
- Web https://en.wikipedia.org/wiki/Splitting_field, The field Ki[X]/(f(X))