Math 2.0

statement proposition

Uniformly continuous functions map Cauchy sequences to Cauchy sequences

Statement

Let D⊆RD \subseteq \mathbb{R} and let f ⁣:D→Rf \colon D \to \mathbb{R} be uniformly continuous. Let (xn)(x_n) be a Cauchy sequence in DD. Then (f(xn))(f(x_n)) is a Cauchy sequence.

Remarks

Given ε>0\varepsilon > 0, take δ\delta from uniform continuity, and then NN with ∣xm−xn∣<δ|x_m - x_n| < \delta for m,n≥Nm, n \ge N. Continuity alone is not enough. The function 1/x1/x on (0,1)(0, 1) maps the Cauchy sequence 1/n1/n to the sequence nn. Mathlib states it as UniformContinuous.comp_cauchySeq.

Explanations

L1 human

Points of a Cauchy sequence crowd closer and closer together. A uniformly continuous function keeps their images crowding together too.

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  1. Limit point of a set definition
  2. Sequence definition
  3. Limit of a function definition
  4. Real sequence definition
  5. Continuity at a point definition
  6. Cauchy sequence definition
  7. Epsilon-delta definition of continuity statement
  8. Uniform continuity definition
  9. Uniformly continuous functions map Cauchy sequences to Cauchy sequences statement

Sources

  1. Web https://en.wikipedia.org/wiki/Uniform_continuity, Properties