Math 2.0

statement proposition

Determinant of the inverse

Statement

Let KK be a commutative ring and let AA be an invertible n×nn \times n matrix over KK. Then det⁡A\det A is a unit of KK, and det⁡(A−1)=(det⁡A)−1,\det(A^{-1}) = (\det A)^{-1}, where det⁡\det is the determinant.

Remarks

The proof applies the product rule to AA−1=InA A^{-1} = I_n: det⁡A⋅det⁡(A−1)=1\det A \cdot \det(A^{-1}) = 1. Over a field, this says det⁡(A−1)=1/det⁡A\det(A^{-1}) = 1 / \det A.

Explanations

L1 human

The inverse matrix undoes the matrix, so it must undo its scaling of volume. If AA scales volume by 33, then A−1A^{-1} scales volume by 1/31/3. So the determinant of the inverse is the inverse of the determinant.

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  1. Identity matrix object
  2. Matrix definition
  3. Vector space definition
  4. Matrix multiplication definition
  5. Square matrix definition
  6. Linear map definition
  7. Invertible matrix definition
  8. Multilinear map definition
  9. Alternating multilinear map definition
  10. Determinant definition
  11. Determinant is multiplicative statement
  12. Determinant of the inverse statement

Sources

  1. Web https://en.wikipedia.org/wiki/Invertible_matrix, Other properties