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  "body": "\n## Proof\n\n1. Let $G$ be a finite group and let $g \\in G$.\n2. The [[cyclic subgroup|0YT586TKXF]] $\\langle g \\rangle$ is a subgroup of $G$.\n3. [[The order of $\\langle g \\rangle$ is the order of $g$|031M8HX7DA]].\n4. By [[Lagrange's theorem|3C53TD]], $|\\langle g \\rangle|$ divides $|G|$.\n5. Thus the order of $g$ divides $|G|$.\n\n## Idea\n\nThe element generates a subgroup whose order is the order of the element. Lagrange's theorem then gives the result.\n",
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