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  "body": "\n## Summary\n\nReduction of order is a method to find a second solution of a homogeneous linear equation from a known one.\nLet $p, q$ be continuous on an open interval $I$, and let $y_1$ be a solution of $y'' + p(x) y' + q(x) y = 0$ with no zero on $I$.\nPut $y = v\\, y_1$. Then $y$ is a solution if and only if $y_1 v'' + (2 y_1' + p\\, y_1) v' = 0$, a first-order linear equation for $v'$.\nOne solution gives $y_2 = y_1 \\int \\frac{e^{-\\int p\\, dx}}{y_1^2}\\, dx$, and $(y_1, y_2)$ is a [[fundamental system|0H4KNNCHPY]] on $I$.\n\n## Remarks\n\nExample: $y_1 = e^{x}$ solves $y'' - 2 y' + y = 0$. Here $p = -2$, so $v' = e^{2x}/e^{2x} = 1$, and $y_2 = x e^x$.\nThe [[Wronskian|0N5NF1RGBP]] of $y_1$ and $y_2$ is $e^{-\\int p\\, dx}$, which has no zero. This is consistent with [[Abel's identity|0VGWKX2JHB]].\nThe same idea lowers the order by one for a linear equation of order $n$.\n\n## Explanations\n\n### L1 human\n\nIf you know one solution, look for a second one as the first one times an unknown function $v$.\nThe terms without derivatives of $v$ cancel, because $y_1$ is a solution.\nWhat remains is a first-order equation for $v'$, which is easy to solve.\n",
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